What is the question actually asking for?
Whatever it is, you need to realize that doubling the volume effectively changes the concentrations of each substance in the vessel. Assuming the equilibrium constant does not change, can you see how doubling the volume will create a non-equilibrium situation... and the reaction will shift accordingly?
If you can't, try calculating the equilibrium constant, K, based on the information given. Then double the volume and calculate Q, the reaction quotient. Is Q = K when the volume is doubled?