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Topic: irreducible representation for B2H4  (Read 3892 times)

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Offline Sch6543

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irreducible representation for B2H4
« on: October 15, 2015, 05:48:42 AM »
I have been given this task, which reads:

Determine with two vectors on the y-bridge-hydrogen atoms as the basic look and the symmetry  to the two oscillations which these hydrogen atoms being perpendicular B2H2 plan.

Some can help me understand how I can find the irreducible representations?

Offline mjc123

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Re: irreducible representation for B2H4
« Reply #1 on: October 15, 2015, 05:58:50 AM »

Offline Sch6543

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Re: irreducible representation for B2H4
« Reply #2 on: October 15, 2015, 06:26:31 AM »
I think so, but I'm not sure

E = 4
C2(z) = 0
C2(y)= 2
C2(x)= 0
i =0
sigma(xy) = 1
sigma(xz) = 0
sigma(yz) = 1


Offline mjc123

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Re: irreducible representation for B2H4
« Reply #3 on: October 15, 2015, 08:48:28 AM »
Are you using the right point group? You look as if you're using D2h, which is the point group of B2H6, not B2H4.
What is the set of four things you're trying to find the representation of?

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