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Topic: Enantiotopic faces at trigonal centers  (Read 1426 times)

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Offline Kate

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Enantiotopic faces at trigonal centers
« on: October 17, 2015, 02:45:46 PM »
Hi.

My book says the following: "The faces are enantiotopic in an unsymmetrically substituted ketone, such as 2-butanone, because they are interconverted by a σ plane."

I can't see this, at all. Could someone explain?

Thanks.

Offline sjb

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Re: Enantiotopic faces at trigonal centers
« Reply #1 on: October 17, 2015, 03:51:27 PM »
Hi.

My book says the following: "The faces are enantiotopic in an unsymmetrically substituted ketone, such as 2-butanone, because they are interconverted by a σ plane."

I can't see this, at all. Could someone explain?

Thanks.

Do you know about re and si faces?

Offline Kate

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Re: Enantiotopic faces at trigonal centers
« Reply #2 on: October 17, 2015, 06:39:37 PM »
Yes, I do. It employs the same logic as R/S but it's used for trigonal centers, like a carbonyl. 

What I don't really understand is how the faces of an unsymmetrically substituted ketone, such as 2-butanone, are interconverted by a σ plane. If you apply a mirror plane to 2-butanone, the image you get isn't superimposable on the first.

Besides, the book also says this: "The faces are diastereotopic in a structure such as either enantiomer of 3-chloro-2-butanone, because there are no symmetry elements that interconvert the faces."

Edit: Nevermind, I think I understand it now. :)
« Last Edit: October 17, 2015, 06:50:36 PM by Kate »

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