I'm studying Sn2 reactions and I know that Iodine is a weaker base and therefore a better leaving group than Br
In an exercise in my book (essential organic chem 3rd edition by paula yurkanis bruice) it asks to see which is more reactive between 1-bromo-2 phenylethane and 1-iodo-2 phenylethane
1-bromo-2 phenylethane and 1-iodo-2 phenylethane look pretty much the same except that one has Br and the other has Iodine
I thought it was 1-iodo-2 phenylethane because it has a better leaving group but the back of the book says its 1-bromo-2 phenylethane
Does the book have an error or am I just not understanding?