[insertwittyname]

One of the step in an iodoform reaction is the abstraction of a proton from the CH₃ group.
However, in a 1,3 diketone, the proton present in between the 2 carbonyl groups (eg. the proton on the third carbon in pent-2,4-dione aka acetylacetone) would be more acidic, and hence more readily abstracted. How does a diketone then give the iodoform reaction?

[orgopete]

You are on the right track. Let's follow the mechanism and see where it leads. Remember, even though enolization occurs that leads to halogenation, hydroxide also adds to the carbonyl group. What can happen?