Some background: I'm about to take my first semester of organic chem at college, so a (relatively) simple explanation will suffice! Textbook is Organic Chemistry by Brown, 7e.
I have a question about the three pi orbitals of acetate; attached is the diagram the textbook provides. My interpretation is that the cartoon representation shows the 2p atomic orbitals of each carbon and oxygen, with in-phase (bottom diagram) and out-of-phase (top diagram) addition. This MO theory addition results in the formation of delocalized pi orbitals. If this is false, please correct me here!
However, either way, why is it that the middle diagram's carbon lacks an atomic orbital? The text says to "note that the central orbital for acetate anion has the 2 electrons in p-orbitals that are only on the oxygens." By "central," is the book referring to the middle diagram? Even if this is true, I still fail to understand why there is no orbital on the carbon. With carbon's sp2 hybridization, where did the unhybridized 2p orbital go?
Furthermore, (this may be a serious rudimentary comprehension problem), are there 3 pi orbitals because 3 atomic orbitals (3 x 2p) are being added?
In gen chem, we drew "energy charts" of MOs and had 4 pi orbitals for 2-atom molecules made of 2nd-period elements: 2 bonding and 2 antibonding. For example, the diagram for O2 would resemble the 2nd attached image. Are there 4 pi orbitals because there are 4 free 2p atomic orbitals for pi bonding?
Sorry for the multitude of intro-level questions – thank you!