I tried converting n in the formula to m/M, but that didn't help because I don't have the mass for MnO4^-
Do you need the mass?
Borek's hint was subtle, but a darn good one.
Hi mikasaur,
I took the hint (assuming I understood it correctly) and have been playing about with Vm = V/n, [Vm = L/mol], where I took the number of moles to be 2, resulting in [Vm = 0.0183/2 = 0.009150000000, which when I use with n = V/Vm gives me a result of 2. Correct - if only I didn't have to divide it by 100 for it to be so.
How would I then work out the mass?
I now have the correct answer for n = 0.02, but only if I write [Vm = 0.0183*1000/2 = 0.009150000000]. I'm not sure if I should do that at all for Vm.
Using m = M * n, I've just worked out the mass to be m = 118.9356*2 = 237.8712, which just seems way off. Converting the formula gives me an n of 2 - again.
Chemistry, chemistry thou art but a mystery!
Perhaps if I'd looked, I would've noticed that 0.02 is the figure for c and not n - as I previously stated. It's been a long day. Back to the drawing board.
Ah, I think I've got it. The ratio is 2:5 - not 2:1. Take the value for n for sodium oxalate: 0.933, divide by 5 and then multiply by 2 to give n for MnO4 = 0.373. Thanks guys!