For problem no. 2 I used equivalence law:...But I don't know to solve the problem from chemical reactions.
E K2Cr2O7 = M/6 = 294/6 = 49
15,9 mg K2Cr2O7 = 15,9 * 10-3 g K2Cr2O7 => E K2Cr2O7 =M/49 = 15,9 * 10-3 / 49 = 3,24 * 10-4 ( equivalent K2Cr2O7) =>
-> 3,24 * 10-4 equivalent H202 => 2* 2,4 * 10-4 equiv. H2O2 = 4,8 * 10-4 E H2O2 =>
2,4 * 10-4 mol H2O2
E H2O2 = M/2
-> 4,8-3,24 = 1,56 * 10-4 E H2O2 => 1,56 * 10-4 E SO2 => 2 * 1,56 = 3,2 * 10-4 mol SO2
M SO2= 3,2 * 10-4 * 64g = 0,12 g SO2
E SO2 = M/2
M BaSO4=233 g/mol, 105,6 mg BaSO4 =105,6 * 10-3 g BaSO4 ->4,5 * 10-4 mol -> 3,2 * 10-4 mol SO2 and 1,3 * 10-4 mol SO3
M SO3 = 80 g/mol
m SO3 = 1,3 * 10-4 * 80 = 0,104 g.
20L air ..0,12g SO2....0,104g SO3
1000L air (1m3)..x g....y g
x=200/20 = 10 g SO2 m3 ... and y=5,2g SO3 m3