V CO2 = V atm * C CO2 = 4.3*1021 * 10-6 L CO2
=> V CO2 = 4.3*1015 L CO2
1 mole CO2 ... 22.4 L
x moles...4.3*1015 L
=> x=1,92*1014 moles CO2
a 9*103 g
6CO2 + 6H2O --> C6H12O + 6O2
6*44g 6*32g
=> a=12.37 kg CO2 / tree-year
=> 12.37*103 / 44 moles = 2,81*102 moles CO2 =>281 moles CO2 / tree-year
total number of moles: nCO2 = 7*109*281 = 1967*109 moles CO2/year
time/year = 1.9*1014/1967*109 = 96.5 years ≈ 97 years.