Hi!!!
I have some doubt reading the electrophilic addition of alkenes on my textbook...
For example my book says that:
CH
3=CHCH
3 + Cl
2 | inert solvent: CH
2Cl
2| -----> CH
3C-ClH-C-ClH-CH
3(addition of two Cl)
BUT if I have as solvent H
2O , I have the addition of a single Cl and of "OH" ,that works as nucleophilic, (that comes from the solvent H
2O, ) + HCl.
So the product has as "nucleophilic" the H
2O and not the Cl
- because water is the solvent, so is "more concentrated" than the solute ( so more odds to interact with the substrate)
Now does all this work also with Halogenidric acids??
For example:
I know that
H
2C=CH
2 + HCl ----> H
3C-CH
2Cl (so I suppose that in THIS reaction H
2O is not the solvent !!?! )
But if I have also the solvent H
2O (so I would have 2 nucleophilic, Cl
- and H
2O ) what is the product??
H
2C=CH
2 + HCl + H
2O (solvent) ---->
H
2O is again more concentrated than Cl
- (a solute) so H
2O should be the nucleophilic?!!?
Thanks.