September 27, 2024, 12:27:00 AM
Forum Rules: Read This Before Posting


Topic: Some exam questions I couldn't do ;-x Help?  (Read 6244 times)

0 Members and 4 Guests are viewing this topic.

Offline mookxi

  • Regular Member
  • ***
  • Posts: 23
  • Mole Snacks: +0/-2
Some exam questions I couldn't do ;-x Help?
« on: June 01, 2006, 10:15:35 PM »
1. Which of the following substances would give a pH of 7.0 in aqueous solution at 25 degrees celcius:

A. KNO3
B: CH3COONa
C. KOH
D: NH4NO3

the answer is A, why? I'm not sure how to do the calculations here or if it's a theory based question.

2. In the reaction of 20g of sulfuric acid with 20g of sodium hydroxide approximately

A. 20g of sodium sulfate are formed
B. 9.1g of sulfuric acid remains
C. 9.0g of water is formed
D. 3.7 of sodium hydroxide reminds

The answer is D.

3. When 100ml of 1.0M HCl are added to 1.0g of granulated zinc at 20 degrees celcius, hydrogen gas is evovled. all of the following will increase the initial rate at which hydrogen gas is released except:

A. increasing the temperature of the 1.0M HCl to 40 degrees celcius
B. using 150ml of 1.0 M HCl instead of 100ml
C. using finely powered zinc instead of granular zinc
D. using 2.0M Hcl instead of 1.0M HCl

the answer is D but i thought it would be B because isn't it increasing the volume therefore the reaction will be slower? Please explain this.

4. Which of the following compounds would be least soluble in water?

A. ethanoic acid
B. ethanol
C. methyl methanoate
D. ethene

the answer is D - ethene, why?

Sorry if that's a lot of questions! Your help would be appreciated!

Offline mike

  • Retired Staff
  • Sr. Member
  • *
  • Posts: 1245
  • Mole Snacks: +121/-35
  • Gender: Male
Re: Some exam questions I couldn't do ;-x Help?
« Reply #1 on: June 01, 2006, 11:01:18 PM »
Quote
3. When 100ml of 1.0M HCl are added to 1.0g of granulated zinc at 20 degrees celcius, hydrogen gas is evovled. all of the following will increase the initial rate at which hydrogen gas is released except:

A. increasing the temperature of the 1.0M HCl to 40 degrees celcius
B. using 150ml of 1.0 M HCl instead of 100ml
C. using finely powered zinc instead of granular zinc
D. using 2.0M Hcl instead of 1.0M HCl

the answer is D but i thought it would be B because isn't it increasing the volume therefore the reaction will be slower? Please explain this.

I would have said B too.


Quote
4. Which of the following compounds would be least soluble in water?

A. ethanoic acid
B. ethanol
C. methyl methanoate
D. ethene

the answer is D - ethene, why?

Think about their polarities..
There is no science without fancy, and no art without facts.

Offline mookxi

  • Regular Member
  • ***
  • Posts: 23
  • Mole Snacks: +0/-2
Re: Some exam questions I couldn't do ;-x Help?
« Reply #2 on: June 01, 2006, 11:04:38 PM »
Thanks Mike. Yup, it's actually B. I checked with other people and they said the answer was wrong. ^_^ yuppie, that's one less I can't do. & thanks. It's ethene right? Cause' it's non-polar, the rest are polar cause' they're hydroxides.

Thanks, & I figured out the rest. ;-D

Quote
3. When 100ml of 1.0M HCl are added to 1.0g of granulated zinc at 20 degrees celcius, hydrogen gas is evovled. all of the following will increase the initial rate at which hydrogen gas is released except:

A. increasing the temperature of the 1.0M HCl to 40 degrees celcius
B. using 150ml of 1.0 M HCl instead of 100ml
C. using finely powered zinc instead of granular zinc
D. using 2.0M Hcl instead of 1.0M HCl

the answer is D but i thought it would be B because isn't it increasing the volume therefore the reaction will be slower? Please explain this.

I would have said B too.


Quote
4. Which of the following compounds would be least soluble in water?

A. ethanoic acid
B. ethanol
C. methyl methanoate
D. ethene

the answer is D - ethene, why?

Think about their polarities..


Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27796
  • Mole Snacks: +1808/-411
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
Re: Some exam questions I couldn't do ;-x Help?
« Reply #3 on: June 02, 2006, 03:09:53 AM »
1. Which of the following substances would give a pH of 7.0 in aqueous solution at 25 degrees celcius:

A. KNO3
B: CH3COONa
C. KOH
D: NH4NO3

the answer is A, why? I'm not sure how to do the calculations here or if it's a theory based question.

B is the only solution of strog acid and strong base.

All other solutions are either of the base (KOH) or salt of the weak acid (acetate) or the weak base (ammonia). Such solutions are never neutral due to hydrolyzis.

(In reality the only answer to this question is: NONE. But that's completely other story.)
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Offline anarchron

  • Regular Member
  • ***
  • Posts: 17
  • Mole Snacks: +5/-5
Re: Some exam questions I couldn't do ;-x Help?
« Reply #4 on: June 02, 2006, 05:05:13 AM »
The reason why KNO3 would give you a solution closest to 7 is because it's a neutral salt as KOH is a strong base and HNO3 is a strong acid.

By the way, are you doing VCE mid years? One of the question looks familar, probably from a STAV.
« Last Edit: June 02, 2006, 05:35:10 AM by anarchron »

Offline mookxi

  • Regular Member
  • ***
  • Posts: 23
  • Mole Snacks: +0/-2
Re: Some exam questions I couldn't do ;-x Help?
« Reply #5 on: June 02, 2006, 05:44:27 AM »
The reason why KNO3 would give you a solution closest to 7 is because it's a neutral salt as KOH is a strong base and HNO3 is a strong acid.

By the way, are you doing VCE mid years? One of the question looks familar, probably from a STAV.

Yes, actually, I am! How did you know? :-D Yes, that was from the STAV 2003 Unit 3 Trial exam paper.

Offline swati

  • Regular Member
  • ***
  • Posts: 80
  • Mole Snacks: +10/-3
  • Gender: Female
Re: Some exam questions I couldn't do ;-x Help?
« Reply #6 on: June 03, 2006, 04:53:33 AM »
2. In the reaction of 20g of sulfuric acid with 20g of sodium hydroxide approximately

A. 20g of sodium sulfate are formed
B. 9.1g of sulfuric acid remains
C. 9.0g of water is formed
D. 3.7 of sodium hydroxide reminds

The answer is D.


The equation would be           
H2SO4   +  2NaOH  --------->   Na2SO4   +   2H2O

20g H2SO4   = 0.204 moles
20g NaOH = 0.5 moles

Now 0.204 moles of H2SO4 will react with (2 * 0.204) = 0.408 moles of NaOH
Therefore ( 0.5 - 0.408 ) = 0.092 moles of NaOH are left
That is ( 0.092 * 40 ) g = 3.68 g of NaOH are left

So the answer is D.

Sponsored Links