September 07, 2024, 08:10:51 PM
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Topic: Determining concentration of phosphate from concentration of phosphorus  (Read 2680 times)

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Offline iamasciencenoob

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I found a 50.0 ml sample of tap water(25.0 ml tap water and 25.0 ml super distilled water) from my home to have 16 ppm of Phosphorus. I am trying to determine how many ppm of PO43- is in the sample. My lab instructor gave us some steps to follow that are not clear to me.

" To find ppm PO43-
  ppm P>mg/L P> MM P, >stoichiometric ratio P:KH2PO43- > MM KH2PO43- > mg/L KH2PO43- > ppm KH2PO43- = ppm PO43-

I understand 1ppm = 1 mg/L, but I am confused on how to continue.

I changed 16 ppm to 16 mg/L
I then converted that to .016 g/L
Next I divided by molar mass of P to get 5.2 x 10^-4 mol/L, but now I am stuck.
« Last Edit: March 07, 2017, 09:14:02 PM by iamasciencenoob »

Offline Dan

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" To find ppm PO43-
  ppm P>mg/L P> MM P, >stoichiometric ratio P:KH2PO43- > MM KH2PO43- > mg/L KH2PO43- > ppm KH2PO43- = ppm PO43-

I disagree with the part in red.

Quote
I understand 1ppm = 1 mg/L, but I am confused on how to continue.

I changed 16 ppm to 16 mg/L
I then converted that to .016 g/L
Next I divided by molar mass of P to get 5.2 x 10^-4 mol/L, but now I am stuck.


Ok so far. Consider:


How many mol P are in 1 mol PO43-?
So given the molar concentration (mol/L) of P, what is the molar concentration of PO43-?
Convert the molar concentration (mol/L) to mass concentration (g/L) of PO43- [hint, you already did the reverse conversion for P].
Convert to ppm.
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Offline iamasciencenoob

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Its a 1:1 molar ratio so I would just take into account the molar masses of P and PO43- when converting?

Offline Borek

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Its a 1:1 molar ratio so I would just take into account the molar masses of P and PO43- when converting?

That's the idea.
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