Thanks for the reply. I think I managed to solve it. It seems rather obvious now so I guess I was just tackling the problem the wrong way. What I did was to look up the composition of natural uranium, which contains 0.7% 235-U. That means that in 1 tone, there'll be 7kg of 235-U. Assuming all the 7kg are extracted (which doesn't happen in actual enrichment, but the question provided no data regarding the content of the isotope in the depleted uranium), the mass of enriched uranium must be 7/0.05=140kg.
The mass of depleted uranium will therefor be 1000-140=860kg