The equilibrium constant for the reaction N2O4 <-> 2NO2 is 0.113. If one were to start with 1 mole of N2O4 at 1 atm pressure and 298 K, what fraction of it would decompose if pressure and temperature are both maintained at 1 atm and 298 K?
By doing a simple equilibrium calculation:
0.113 = (PNO2)2 / (PN2O4)
= (2x)2 / (1 - x)
I get a value of 0.155 for x.
However, the solution my instructor gives:
0.113 = (PNO2)2 / (PN2O4)
= (2x / 1 + x)2 / ( (1 - x) / (1 + x))
Where (1 + x) represents the total pressure of the system at equilibirum, results in an x value of 0.166. Which solution is correct and why?