1) the reaction below releases 56.6kj of heat at 298k for each mole of NO2 formed at a constant pressure of 1 atm. what is the standard enthalpy of formation of NO2 given the standard enthalpy of NO is 90.4kj mol
2NO + O2 ---> 2NO2
You can visualise the question in this manner:
1. N
2 + O
2 -> 2 NO
2. 2NO + O
2 -> 2NO
2so total dH from step 1 to 2 is:
dH
1 = 2 dH
f,NO = 2 mol NO x 90.4kJ/mol NO = 180.6 kJ
dH
2 = 2 dH
r = 2 mol NO
2 x -56.6kJ/mol NO
2 = -113.2 kJ
dH = dH
1 + dH
2In fact, steps 1 and 2 can be sum up to produce:
N
2 + 2O
2 -> 2NO
2Hence, dH = 2 x dH
f,NO2dH
f,NO2 = dH/2
2) a 200g of copper at 100 degrees celsius is dropped into 1000g of water at 25 degrees celsius. what is the final temp of the system?
specific heat of water is 4.18J and copper is 0.400 J
The final temperature (T) of the water and the copper block must be the same, else heat transfer will not stop. The above problem can be solved by using an energy balance, ie.
heat absorbed by water = heat lost by copper block.
m
waterCp
water(T-T
ini,water) = m
copperCp
copperr(T
ini,copper - T)
where m is mass, and Cp is the specific heat capacity.
3) if the equilibrium constant for A + B <===> C is 0.123, the equilibrium constant when 2C <===> 2A + 2B is?
1. A + B <===> C
K
1 = [ C ] / [ A ] [ B ]
2. 2C <===> 2A + 2B is?
K
2 = [ A ]
2 [ B ]
2 / [ C ]
2 = ( [ A ] [ B ] / [ C ] )
2 = ( [ C ] / [ A ] [ B ] )
-2 = (K
1)
-2