Hi everyone!
I'm working through two questions about limiting reagents, and I got the first, but the second is really confusing as it deals with 3 reactants, where my teacher only showed us how to solve with 2. Could anyone shed some light on this process? I have included the first question too so you guys can see my process!
Use mole ratios to identify the limiting reagent in the following reactions:
a) 2.75 mol of sodium mixes with 4.25 mol of water to form sodium hydroxide and hydrogen gas.
Balanced equation:
2Na + 2H2O -> 2NaOH + H2
Number of moles of each reactant:
Na=2.75 mol (H2O)=4.25 mol
Mole ratio between reactants (assume that all of the H2O did react):
In the reaction, 2 mols of H2O requires 2 mols of Na to react
4.25 mols H2O will require z mols Na to react
z=4.25 mol × (2/2) =4.25 mol
The water needs 4.25 moles of sodium, yet there is only 2.75 moles available. There will not be enough sodium to use all the water; sodium is the limiting reagent.
b) 2.5 mol of CaO mixes with 3.0 mol of SO2 and 2.0 mol of O2 to produce CaSO4.
Balanced equation:
2CaO + 2SO2 + O2 -> 2CaSO4
Number of moles of each reactant:
CaO=2.5 mol SO2 =2.75 mol O2 =2.0 mol
I know the next step is the actual calculation part, and I have determined that the limiting reagent is CaO, but I dont know how to show it!
Thanks in advance!