Well that is very naughty of them. Do they give a reaction equation? If so you must assume that the rate is defined in terms of that equation, and
Rate = (1/α)*d[X]/dt
where α is the coefficient of reagent X in the equation (negative for reactants, positive for products).
So if the equation is, say, 2A
B and
Rate = (-1/2)*d[A]/dt = k[A]
2then d[A]/dt = -2k[A]
2If, however, you write (as I would) d[A]/dt = -k'[A]
2then obviously k' = 2k
Now solve the differential equation and get the half-life, and you get
t
1/2 = 1/(k'[A]
0) = 1/(2k[A]
0)