[habetsth]

I have difficulties finding the mechanism of the state solid synthesis of LiMn2O4 in literacy.

Starting from Lithium Acetate and Manganese Acetate, I've found the general equation easily: Li(Ac) + 2 Mn(Ac)2 + 43/4 O2 --> LiMn2O4 + 10 CO2 + 15/2 H20

What I can't find is a mechanism of this reaction. I know that Mn is oxidized and Li keeps its oxidation state. Is Mn304 a precursor in this reaction ? Is Mn2O3 a by-product ?

Thanks

[chenbeier]

Are you sure it is LiMn₂O₄ and not LiMnO₄ or Li₂MnO₄?
In your compound the average oxidation number of manganese is 3.5 what means the oxidation number of each manganese atom is different. 3 to 4 or 2 to 5 or something.

[habetsth]

Are you sure it is LiMn₂O₄ and not LiMnO₄ or Li₂MnO₄?
In your compound the average oxidation number of manganese is 3.5 what means the oxidation number of each manganese atom is different. 3 to 4 or 2 to 5 or something.

Yea, that's right, LiMn₂O₄. It is used in Li-ion batteries for the cathode and the oxidation state is 3.5 due to different oxidation numbers of the 2 manganese atoms