December 30, 2024, 12:19:29 PM
Forum Rules: Read This Before Posting


Topic: How to analyse an IR and NMR to eliminate the Isomers  (Read 6076 times)

0 Members and 1 Guest are viewing this topic.

Offline aag

  • New Member
  • **
  • Posts: 3
  • Mole Snacks: +0/-0
How to analyse an IR and NMR to eliminate the Isomers
« on: March 22, 2018, 12:01:22 AM »
So, I have an assignment that is about 4-chlorobenzaldehyde but I cannot find much information on it.

I have to deconstruct and analyse my IR but there is no information the collaborates with the 1300-1000 region. I was also wondering if someone could help with a quick analysis. The IR is different from most found on the internet and I was also wondering why that is (but the NMR is the same).

For the IR and the NMR we have to explain why the compound is 4-chlorobenzaldehyde and not its other isomers such as 2-chlorobenzaldehyde or 3-chlorobenzaldehyde.
« Last Edit: March 22, 2018, 01:31:59 AM by aag »

Offline wildfyr

  • Global Moderator
  • Sr. Member
  • ***
  • Posts: 1778
  • Mole Snacks: +203/-10
Re: How to analyse an IR and NMR to eliminate the Isomers
« Reply #1 on: March 22, 2018, 09:46:26 AM »
Here is a website I found (in ten seconds) on using FTIR to distinguish isomers (hint look between 900 and 700)
http://www.spectroscopyonline.com/distinguishing-structural-isomers-mono-and-disubstituted-benzene-rings-0?pageID=2

Why do you need to evaluate the 1000-1300 region?

If you have the NMR then distinguishing isomers should be dead easy.

Sponsored Links