[lachie123]

No Iam not sure , hopefully its is in a solid form though. Thankyou for you help.

[lachie123]

thanks i get most of it now. but just one last question..
once i have done the titrations how do i use the titration infomation to find the mass of the Na2CO3

[Borek]

thanks i get most of it now. but just one last question..
once i have done the titrations how do i use the titration infomation to find the mass of the Na2CO3

As Alberto wrote: you start with the reaction equation.

[lachie123]

Could you please enlighten me on this particular equation and how i use it to find the mass form the titration results.

[lachie123]

Is there any chance of a response ,Please since is it 1am where i live and iam very tired ,thankyou.

ANYone please..!! I am realy in need of some sleep.

[Alberto_Kravina]

The reaction equation is written in the link that Borek posted, only that only the acid (in your case hydrochloric) is written as "H⁺" and the carbonate (in your case sodium carbonate) is written as "CO₃^2-". Also, it is explained that one mole of carbonate requires two moles of acid (assuming that you use a monoprotic acid like in your case) which should make clear how to calculate the mass of sodium carbonate afterwards.

Hint for alculations: At equivalence point: n_eq(Na₂CO₃) = n_eq(HCl)

[lachie123]

i titrated the mixture and the teacher let us do the calculations at home.

My mass of mixture was 8.89g
and my disovled mixture volume was made up to 500mls
my Aliquot volume used was 20 mls

I used methol Orange as a indicator and my average amount of 0.2 mole HCl used to titrate was 7.35 mls.

How do i now use this info to find the mass of Na2CO3 so i can find the mass of the NaCL

[Borek]

How do i now use this info to find the mass of Na2CO3 so i can find the mass of the NaCL

Alberto pointed out to you all necessary information.

[lachie123]

I can't understand the infomation , could someone please help me understand the process a little more clearly..

[xiankai]

based on the reaction

2 HCl + Na₂CO₃ --> H₂O + 2 NaCl
OR
2H₃O⁺ + CO₃^2- --> H₂O

mole ratio is

2HCl ? Na₂CO₃

assuming all the Na₂CO₃ reacted
assuming titration end-point was reached accurately

we can conclude the reaction took place in exact mole ratio as described above.

given the moles of HCl that reacted, you can find the moles of Na₂CO₃ that reacted, based on mole ratio.

since mass of mixture = mass of Na₂CO₃ + mass of NaCl

mass of NaCl = mass of mixture - mass of Na₂CO₃

it cant get any simpler, i hope

[lachie123]

thanks for that dude.   THAT HELPED ME SOOO MUCH.  everyone give xiankia a heap of scooby snacks he deserves them.!!!

[lachie123]

Who the f&#$ gavew me a negitive scoob snack , if i ever see u i will stick a 1L conical flask up your ass backwards.

[DrCMS]

I just took one from you for being an annoying little sod. 

People tried to help you but you just wanted somebody to do it for you and eventually xiankai took pity on you and did it all for you. 

This forum is not here so lazy people can get their homework done for them it's here to show you how to do it.

Feel free to email me for my address and we can have a chat about that flask.

[lachie123]

Give me a break , u [...] , i failed the  test anyway ( my results were not accuarte enough)

[Borek]

Give me a break , u [...] , i failed the  test anyway ( my results were not accuarte enough)

Topic locked, 5 days ban.