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Topic: Minéral carbonation  (Read 2883 times)

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Offline Icanfly

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Minéral carbonation
« on: May 04, 2018, 01:14:17 PM »
Hello ,I try to write  the chemical equation of this reaction:

Mg Si2 O5 (OH)4+xHCl+yNaOH+zCO3 ->

knowing that I found

Mg(OH)2+2NaOH-->Na [Mg(OH)4]

Mg(OH)2+2CO2-->Mg(CO3)2

Mg3Si2O5(OH4)+6HCl-->3MgCl2+5H2O+2SiO2

So I conclude the chemical reaction is equal to

MgCl2+H2O+SiO2+Na2[Mg(OH)4]+Mg(HCO3)


Someone can say me if what I rote is corrected or no please.



Offline Borek

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Re: Minéral carbonation
« Reply #1 on: May 04, 2018, 02:35:15 PM »
xHCl+yNaOH

Doesn't make much sense, you can as well add some NaCl and a bit a the excess reagent.

Please elaborate on what you are really trying to do.
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Offline billnotgatez

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Re: Minéral carbonation
« Reply #2 on: May 04, 2018, 04:15:22 PM »
Is this common in a reaction formula
CO3
by itself?

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