If 4 cm3 potassium manganate(VII) is needed for 25cm3 hydroxyammonium sulphate+25cm3 dilute sulphuric acid.
How to calculate
a)concentration(mol dm-3) of ion MnO4-
b)concentration of ion Fe2+ in solution of hydroxyammonium sulphate with excess iron(III) ammonium sulphate and dilute sulphuric acid
c)mass of ion iron(II) in 1 dm3 of hydroxyammonium sulphate with excess iron(III) ammonium sulphate and dilute sulphuric acid
d)no moles of iron (II) ions required to oxidise 1 mol of hydroxyammonium ion.
Instead of giving Fe3+ + 2 NH3OH+ + 2H+ + 5e- --> Fe2+ + N2O + H2O + 4 H2
My teacher gives us this one 4 Fe3+ + 2 NH3OH+ --> 4 Fe2+ + N2O + H2O + 6H+