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Topic: nodal surfaces  (Read 12043 times)

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Offline jennielynn_1980

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nodal surfaces
« on: July 25, 2006, 07:05:03 PM »
How many nodal surfaces are there for
a) 2s orbital
b) 3px orbital

My answer:
a) 0 because it a spherically shape with no nodes or points passing through the nucleus
b) 1 because it has 1 node where it passes through the nucleus

I really have no idea if this is correct.  I dont' think I really understand this concept that well.  If anyone has a link explaining it somewhat simplistically that would be great.
Thanks :)

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Offline Mitch

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Re: nodal surfaces
« Reply #1 on: July 25, 2006, 07:09:28 PM »
The 1s orbital has 0 nodes. But, the 2s orbital will have 1 node. View this site. http://winter.group.shef.ac.uk/orbitron/
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Offline Yggdrasil

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Re: nodal surfaces
« Reply #2 on: July 26, 2006, 02:25:27 AM »
As Mitch alluded to, there are two types of nodes, radial nodes and angular nodes.  The number of radial nodes depends on n, the principal quantum number.  There are n-1 radial nodes.  The number of angular nodes depends on l, the angular quantum number.  There are l angular nodes (i.e. s orbitals have 0 angular nodes, p orbitals have 1, d orbitals have two, f orbitals have 3, etc).
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