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Topic: SOCl2 addition  (Read 4131 times)

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Offline oxygeniscoool

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SOCl2 addition
« on: March 23, 2019, 07:59:39 AM »
How to know which intermediate that is formed in the first step (H -> J)? Which first steps are first in this mechanism?

Offline Mitch

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Re: SOCl2 addition
« Reply #1 on: March 23, 2019, 08:32:52 AM »
The thionyl chloride converts the carboxylic acid to an acid chloride. Can you attempt to draw the mechanism knowing that?
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Offline oxygeniscoool

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Re: SOCl2 addition
« Reply #2 on: March 23, 2019, 08:53:20 AM »
So, the sulfur atom is attacked?
« Last Edit: March 23, 2019, 09:25:00 AM by oxygeniscoool »

Offline oxygeniscoool

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Re: SOCl2 addition
« Reply #3 on: March 23, 2019, 09:25:55 AM »
The thionyl chloride converts the carboxylic acid to an acid chloride. Can you attempt to draw the mechanism knowing that?

I don't really understand the process after all. Is NH2 attacked?

Offline Mitch

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Re: SOCl2 addition
« Reply #4 on: March 23, 2019, 09:47:45 AM »
No, the amine is not attacked first. I think you need to review SOCl2 chemistry: https://www.masterorganicchemistry.com/2011/12/03/reagent-friday-thionyl-chloride-socl2/
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Offline oxygeniscoool

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Re: SOCl2 addition
« Reply #5 on: March 23, 2019, 09:58:42 AM »
No, the amine is not attacked first. I think you need to review SOCl2 chemistry: https://www.masterorganicchemistry.com/2011/12/03/reagent-friday-thionyl-chloride-socl2/

Okay, thanks!

Offline wildfyr

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Re: SOCl2 addition
« Reply #6 on: March 23, 2019, 10:08:19 AM »
I gotta say, it is a little weird to expect a acyl chloride and aniline to exist together. I guess the amine is protonated quite quickly but even so... I would have expected some amount of oligomer if you don't move fast.
« Last Edit: March 23, 2019, 10:26:31 AM by wildfyr »

Offline OrganicDan96

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Re: SOCl2 addition
« Reply #7 on: March 23, 2019, 10:13:09 AM »
wouldn't the aniline be protonated all along by the carboxylic acid?

Offline wildfyr

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Re: SOCl2 addition
« Reply #8 on: March 23, 2019, 10:29:06 AM »
Just a plain amine, yes. But the Wikipedia page of anthranilic acid suggests they are present in both forms in the absence of another acid or base.

Aniline is too weak a base to fully deprotonate a carboxylic acid at 1eq.

Edit: here's the paper wiki is referring to https://royalsocietypublishing.org/doi/10.1098/rspa.1968.0003

DOI:10.1098/rspa.1968.0003
« Last Edit: March 23, 2019, 10:45:30 AM by Mitch »

Offline kriggy

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Re: SOCl2 addition
« Reply #9 on: March 25, 2019, 04:40:06 AM »
I think the aniline is not really THAT reactive (I had some problems making amides without additional base). I mean there is highly deactivating group on the ring (not in conjugation though) and methyl grop ortho to amine proceting some steric hinderance. Also, methanol is in high excess.

Also, its possible that the reaction procees via formation of methylchloride from methanol and then alkylation of the carboxylic acid?

Offline clarkstill

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Re: SOCl2 addition
« Reply #10 on: March 25, 2019, 04:56:23 AM »
I agree anilines aren't all that nucleophilic (certainly nowhere near as nucleophilic as alkyl amines). However, they are almost certainly more nucleophilic than carboxylic acids, which raises the question why does the SOCl2 react with the carboxylic acid not the aniline? Or does it react reversibly with the aniline? Maybe it's just early in the morning and I'm being dumb.

Offline wildfyr

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Re: SOCl2 addition
« Reply #11 on: March 26, 2019, 02:23:27 AM »
Usually a huge excess of thionyl chloride is used in chlorination reactions. I typically use it as the solvent along with a catalytic drop of DMF.

So yeah, probably some gets consumed making the ammonium chloride salt, but there's plenty left to make acid chloride.

Kirggy, under acidic conditions that methyl chloride reaction doesn't sound very good. It's a very ordinary way to make esters to make the acid chloride, not really isolate it, then dump in a bunch of your desired alcohol.
« Last Edit: March 26, 2019, 08:17:04 AM by wildfyr »

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