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Topic: How are there more outputted Oxygens in a reaction than Inputted?  (Read 1836 times)

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Offline str0k3h

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How are there more outputted Oxygens in a reaction than Inputted?
« on: April 23, 2019, 07:43:22 PM »
Hi, I wanted to know how in the formation of manganese heptoxide (Mn2O7) from H2SO4 and KMnO4 more Oxygens are outputted than inputted, since we use those two chemicals and the chemical reaction is
H2SO4 + KMnO4 ----> Mn2O7+H2O+2KHSO4. From what I can see I inputted 8 Oxygens and there are 12 in the final compounds.
Thank you a lot.
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Offline billnotgatez

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Re: How are there more outputted Oxygens in a reaction than Inputted?
« Reply #1 on: April 23, 2019, 10:29:58 PM »
Per forum rules here are Hints
In your formula
H2SO4 + KMnO4   :rarrow:  Mn2O7+H2O+2KHSO4
the total number of oxygen atoms on the right side is not 12 and your equation is not balanced.
Below is an example of a balanced equation
2H2 + O2  :rarrow:  2H2O
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Offline str0k3h

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Re: How are there more outputted Oxygens in a reaction than Inputted?
« Reply #2 on: April 23, 2019, 10:32:57 PM »
I'm so sorry
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Offline billnotgatez

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Re: How are there more outputted Oxygens in a reaction than Inputted?
« Reply #3 on: April 23, 2019, 10:56:50 PM »
Quote from: str0k3h on April 23, 2019, 10:32:57 PM
I'm so sorry

No worries

What are your thoughts in solving the question?
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Offline Borek

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Re: How are there more outputted Oxygens in a reaction than Inputted?
« Reply #4 on: April 24, 2019, 02:49:26 AM »
As Bill suggested - you started with a non balanced equation, so your conclusion is incorrect. As they say - GIGO, Garbage In, Garbage Out ;)

This equation can be correctly balanced and then the problem disappears.
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