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Topic: 4-methylpent-4-enal + NaCN H[sub]2[/sub]O, HCl  (Read 1660 times)

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Offline Notsmartenough

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4-methylpent-4-enal + NaCN H[sub]2[/sub]O, HCl
« on: April 30, 2019, 07:27:18 PM »
That example is in exercise 10 from Chapter 6 in Clayden Organic Chemistry. Unfortunately in a Solutions Manual this particular reaction was omitted. I suppose the product will be 5-chloro-2-hydroxy-5-methylhexanenitrile.

On the other hand I do not know if "HCl" written under the rxn arrow means either there is only a quantity to "neutralize" NaCN into HCN and NaCl added, or we should be considering electrophilic addition as a secondary reaction?
« Last Edit: April 30, 2019, 07:40:08 PM by Notsmartenough »

Offline AWK

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Re: 4-methylpent-4-enal + NaCN H[sub]2[/sub]O, HCl
« Reply #1 on: May 01, 2019, 01:25:03 AM »
Without heating, the hydrolysis of nitrile does not take place
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Offline Notsmartenough

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Re: 4-methylpent-4-enal + NaCN H[sub]2[/sub]O, HCl
« Reply #2 on: May 01, 2019, 12:22:35 PM »
Last question what about addition of HCl to the double bond? I suppose HCl is just to create more reactive HOCl, but I might be wrong.

Offline AWK

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Re: 4-methylpent-4-enal + NaCN H[sub]2[/sub]O, HCl
« Reply #3 on: May 01, 2019, 12:50:31 PM »
Last question what about addition of HCl to the double bond?
I suppose HCl is just to create more reactive HOCl, but I might be wrong.
1. Did you use a dry HCl?
2. You are wrong. Elemental chlorine with water forms a mixture of HCl and HOCl.
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Offline Notsmartenough

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Re: 4-methylpent-4-enal + NaCN H[sub]2[/sub]O, HCl
« Reply #4 on: May 02, 2019, 12:05:35 PM »
Last question what about addition of HCl to the double bond?
I suppose HCl is just to create more reactive HOCl, but I might be wrong.
1. Did you use a dry HCl?
2. You are wrong. Elemental chlorine with water forms a mixture of HCl and HOCl.

My mistake, I was thinking about HCN not HOCl. (NaCN + HCl)

According to dry HCl, are you suggesting the reaction of an alkene with hydrogen halide will not occur in aqueous phase?

Offline AWK

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Re: 4-methylpent-4-enal + NaCN H[sub]2[/sub]O, HCl
« Reply #5 on: May 02, 2019, 06:49:00 PM »
This is two steps reaction - the addition of CN- and neutralization.
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Offline Notsmartenough

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Re: 4-methylpent-4-enal + NaCN H[sub]2[/sub]O, HCl
« Reply #6 on: May 02, 2019, 08:32:26 PM »
So the double bond stays untouched, and the product is just a cyanohydrin. Thank you for your help.

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